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320x^2+36900x+200000=0
a = 320; b = 36900; c = +200000;
Δ = b2-4ac
Δ = 369002-4·320·200000
Δ = 1105610000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1105610000}=\sqrt{5290000*209}=\sqrt{5290000}*\sqrt{209}=2300\sqrt{209}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36900)-2300\sqrt{209}}{2*320}=\frac{-36900-2300\sqrt{209}}{640} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36900)+2300\sqrt{209}}{2*320}=\frac{-36900+2300\sqrt{209}}{640} $
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